Question

How do you find the domain and range of `ln(x - 3) + 2`?

Answer 1

Since the `ln` function is only defined for positive arguments, the domain is `x>3` with no upper limit, or in other words `3 < x < oo`.

Explanation:

The `ln` function can reach any value from `-oo->+oo` (even if it rises very slowly), which will not change is we add `2`. So this is the range .
graph{ln(x-3)+2 [-37.34, 55.15, -23.9, 22.35]}