What is the major product formed when HBr is added to Pent-2-ene?
On adding HBr to Pent-2-ene (CH3-CH2-CH=CH-CH3); The major product formed is 2-Bromopentane whose carbocation has 5- Hyperconjugates and it is in accordance with MARKOWNIKOVA rule which states electrophilic addition to an unsymmetrical alkene always occurs through the formation of a more stable carbocation intermediate which I agree, but at the same time, I get confused when I apply the other statement of M.rule, which says the negative part of the addendum goes to the carbon with lesser H atoms. But here both carbons have one H each.. so please correct me!
On adding HBr to Pent-2-ene (CH3-CH2-CH=CH-CH3); The major product formed is 2-Bromopentane whose carbocation has 5- Hyperconjugates and it is in accordance with MARKOWNIKOVA rule which states electrophilic addition to an unsymmetrical alkene always occurs through the formation of a more stable carbocation intermediate which I agree, but at the same time, I get confused when I apply the other statement of M.rule, which says the negative part of the addendum goes to the carbon with lesser H atoms. But here both carbons have one H each.. so please correct me!
1 Answer
see below
Explanation:
Markovnikov rule is only an empirical rule to forecast the addition on a double bond of an alchene. It is regulated from the inductive effect, and the carbocation that is more stable will be formed. between
the second carbocation is more stabe than the first, and you will have preferably it.
This is because
