How do you find the Vertical, Horizontal, and Oblique Asymptote given #(x^2+1)/ (3x-2x^2)#?
1 Answer
Oct 17, 2017
Vertical asymptote
Horizontal asymptote
No slant asymptote.
Explanation:
Vertical Asymptote: Equate Denominator to zero.
Horizontal asymptote:
Since degrees of denominator and numerator are same, horizontal asymptote is obtained by dividing leading coefficients of highest degree numerator and denominator.
Slant or oblique asymptote :
Since numerator is not one degree above the denominator polynomial, there is slant or oblique asymptote.
graph{(x^2+1)/(3x-2x^2) [-10, 10, -5, 5]}