How do you evaluate sine, cosine, tangent of #750^circ# without using a calculator?

Question

7986 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-20T22:18:47

#sin (30)^0 = 1/2#

#cos 30^0 = sqrt3/2#

#tan 30^0 = 1/ sqrt3#

#750^0 = 360^0 + 360^0 + 30^0 = 30^0#

Now you can find the value of #30^0#.

#sin (30)^0 = 1/2#

#cos 30^0 = sqrt3/2#

#tan 30^0 = 1/ sqrt3#