Question

How do you find the roots, real and imaginary, of `y= -3x^2-16x +8` using the quadratic formula?

Answer 1

Roots are `**5.7936, -0.4603**`

Explanation:

Standard form of equation is `ax^2 + bx + c = 0`
Roots are`= ((-b) +- sqrt(b^2 -(4ac)))/(2a)`

Given equation is `-3x^2 -16x + 8 = 0`
`a = -3, b = -16, c = 8`

`x =( -(-16) +- sqrt((-16)^2 - (4*(-3)8)))/(2*(-3))`

`x = (16 +- sqrt(256 + 96))/6`

`x = (16 +- sqrt352)/6`

`x = 5.7936, -0.4603`