Question #37377

1 Answer
Y
Oct 22, 2017

#v_f=-11.96# #m"/"s#

Explanation:

First we can write out the given information:
#v_i=0# #m"/"s#
#Deltat=2.6# #sec#
#a=-4.6# #m"/"s^2#

Since we are looking for #v_f#, we can use the equation:
#v_f=v_i+aDeltat#

Plugging in the given values, we get:
#v_f=0+(-4.6)(2.6)=-11.96# #m"/"s#

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