Question

How do you find the derivative of `y=-(2x+3+4x^-1)^-1`?

Answer 1

`y’ = (2-(4/x^2))/(2x + 3 + (4/x))^2`

Explanation:

`y= -(2x + 3 + 4x^-1)^-1`

`y’ = (- (-1) (2x + 3 + x^-1)^-2) * (2 + 4 (-1)x^-2)`

`y’ =(1/ (2x + 3 + (4/x))^2) * (2 - (4/x^2))`

`y’ = (2-(4/x^2))/(2x + 3 + (4/x))^2`