What is the Cartesian form of #(12,(-7pi)/3))#?

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Answer 1 · 2017-10-25T12:47:39

#(5 , -10.39 )#

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It can be seen from the diagram that the x coordinate of P is #rcos(theta)# and the y coordinate of P is #rsin(theta)#

So:

#x=rcos(theta)#

#y=rsin(theta)#

From example:

#x=12cos((-7pi)/3)=-6#

#y=12sin((-7pi)/3)=-10.39# (2 .d.p.)

Cartesian coordinate:

#(5 , -10.39 )#