What is the Cartesian form of #( -1 , ( 15pi)/4 ) #?

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Answer 1 · 2017-10-25T12:52:31

#( -0.71 , 0.71 )#

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It can be seen from the diagram that the x coordinate of P is #rcos(theta)# and the y coordinate of P is #rsin(theta)#

So:

#x=rcos(theta)#

#y=rsin(theta)#

From example:

#x=-1cos((15pi)/4)=-0.71# (2 .d.p.)

#y=-1sin((15pi)/4)=0.71# (2 .d.p.)

Cartesian coordinate:

#( -0.71 , 0.71 )#