How do you simplify #(2x^0y^2)^-3*2yx^3# and write it using only positive exponents?

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Answer 1 · 2017-10-26T14:02:21

#(y^-5x^3)/4#

#(2x^0y^2)^-3 * 2yx^3#

laws of indices:

#(a^m)^n = a^(mn)#
#a^m * a^n = a^(m+n)#

#(x^0)^-3 = x^0 = 1#

#(y^2)^-3 = y^-6#

#2^-3 = 1/8#

#(2x^0y^2)^-3 = y^-6/8#

#y^-6/8 * 2yx^3 = 2*y^-5*x^3*1/8#

#=(y^-5*x^3)/4#

#=(y^-5x^3)/4#