Question

Question #ad1dc

Answer 1

The answer is pairs of numbers of the type `3n+-3`.

Explanation:

`a+b=6n`
`a-b=6`

if we sum both equations we obtain:

`2a=6(n-1)->a=3(n-1)=3n-3`

Replacing a in one of the statements we obtain:

#b=6n-a=6n-(3n-3)=3n+3

So we can have pairs (a, b) equal to:

(-3,3); (0,6); (3;9) etc...