How do you find the volume of a solid that is enclosed by #y=secx#, #x=pi/4#, and the axis revolved about the x axis?

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Answer 1 · 2017-08-29T20:34:56

Note that #secxgt=1# for all values of #x#.

Here's the graph of #secx#:

graph{secx [-14.24, 14.24, -7.12, 7.12]}

There is no region bounded by #secx#, #x=pi//4# and the axis without another vertical line in the form #x=a# to serve as a boundary of our region.

We don't have enough information to complete this problem.

Answer 2 · 2017-11-01T19:08:50

I have solved this way:
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