How do you solve #(2x+1)(2x+3) = -2x(2x+1)# ?

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Answer 1 · 2017-11-04T19:03:15

#x=-1/2" "# or #" "x=-3/4#

Given:

#(2x+1)(2x+3) = -2x(2x+1)#

Note that if #x=-1/2# then #(2x+1) = 0# and both sides of the equation are zero. So #x=-1/2# is one solution.

If #x != -1/2# then #(2x+1) != 0#. Divide both sides of the equation by #(2x+1)# to get:

#2x+3 = -2x#

Add #2x-3# to both sides to get:

#4x = -3#

Divide both sides by #4# to get:

#x = -3/4#