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Answer 1 · 2017-11-05T11:33:33

$64 + 32 x + 4 x^{2}$ $64 + 32x + 4x^2$

According to the order of operations:

First: terms/factors between brackets, which is: $4 + x$ $4 + x$ , but you can't solve this furthermore, so you leave it like this.

Second: powers or square roots, which is ${(4 + x)}^{2}$ $(4 + x)^2$ . It's a special product (a perfect square trinomial). So it becomes

$16 + 8x + x²$

since $(a + b)^2 = (a^2 + 2ab + b^2)$

Third: multiplications or divisions, which is $4(4 + x)^2$ We already calculated that

$(4 + x)^2 = 16 + 8x + x^2$

So then multiply the whole polynomial with $4$

$4 * 16 + 4 * 8x + 4 * x^2 = 64 + 32x + 4x^2$

Fourth: additions or subtractions, you don't have any. So

$64 + 32x + 4x^2$

is the final answer.