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Answer 1 · 2017-11-06T15:12:39

#2.1 dm^3#

#12 cm^3=0.012 dm^3# of "0.98 mol dm^-3 H_2 SO _4#

1

Will use the useful formula:

#C=n/V ->0.98=n/0.012 -> n=0.1176 mol#

Then we will use formula again to know how much volume of the first solution will need to prepare the second:

#C=n/V ->0.056=0.1176/V -> V=2.1 dm^3#

#2#

Ww will use the other expression:

#C1*V1=C2*V2#

#0.98*0.012=0.058*V2 ->V2=2.1 dm^3#