Some very hot rocks have a temperature of #540 ^o C# and a specific heat of #270 J/(Kg*K)#. The rocks are bathed in #15 L# of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?

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Answer 1 · 2017-11-07T14:34:47

273.3 kg

Density of water at #100°C# is #958.05# #"kg/m"^3#

#"Mass = Density × Volume"#

#"Mass of water" = 958.05 (kg)/m^3 × 15 × 10^-3 m^3 = 14.370 kg#

#"Heat released by rocks = Heat absorbed by boiling water"#

#MSdT = mL#

#M = (mL) / (SdT)#

#M = (14.370 kg × 2260 J/g) / (270J/(kg K) × (540 - 100) K] = 273.3 kg#