How do you multiply #(-4x+3y)^2#? Algebra Polynomials and Factoring Special Products of Polynomials 1 Answer F Nov 8, 2017 #16x^2-24xy+9y^2# Explanation: You can use the formula: #(x+y)^2= x^2+2xy+y^2# In this case the "x" will be #-4x# and the "y" will be #3y# #(-4x)^2+(2)(-4x)(3y)+(3y)^2# #=16x^2-24xy+9y^2# Answer link Related questions What are the Special Products of Polynomials? What is a perfect square binomial and how do you find the product? How do you simplify by multiplying #(x+10)^2#? How do you use the special product for squaring binomials to multiply #(1/4t+2 )^2#? How do you use the special product of a sum and difference to multiply #(3x^2+2)(3x^2-2)#? How do you evaluate #56^2# using special products? How do you multiply #(3x-2y)^2#? How do you factor # -8x^2 +32#? How do you factor #x^3-8y^3#? How do you factor # x^3 - 1#? See all questions in Special Products of Polynomials Impact of this question 2549 views around the world You can reuse this answer Creative Commons License