Question

How do you write the equation in point slope form given a line parallel to y= -2 + 3x passing through (-2,8)?

Answer 1

`y-8=3(x+2)`

Explanation:

`• " Parallel lines have equal slopes"`

`y=3x-2" is in "color(blue)"slope-intercept form"`

`•color(white)(x)y=mx+b`

`"where m is the slope and b the y-intercept"`

`rArry=3x-2" has slope "m=3`

`"hence a parallel line will have slope "m=3`

`"the equation of a line in "color(blue)"point-slope form"` is.

`•color(white)(x)y-y_1=m(x-x_1)`

`"where m is the slope and "(x_1,y_1)" a point on the line"`

`"here "m=3" and "(x_1,y_1)=(-2,8)`

`y-8=3(x-(-2))`

`rArry-8=3(x+2)larrcolor(red)"in point-slope form"`