How do you simplify #((3mp^3)/(7q^2))^2#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Tamir E. Nov 15, 2017 #((3mp^3)/(7q^2))^2=((9m^2p^6)/(14q^4))# Explanation: #((3mp^3)/(7q^2))^2=((3mp^3)/(7q^2))*((3mp^3)/(7q^2))=# #=> ((3^2m^2(p^3)^2)/((7)^2(q^2)^2))# #=> (((3*3)(m*m)(p^3*p^3))/((7*7)(q^2*q^2)))# Power's laws: #(x^a)^b=x^(a*b)# #(x^a)(x^b)=x^(a+b)# #=> (((9)(m^2)(p^(3+3)))/((14)(q^(2+2))))# #=> (((9)(m^2)(p^(6)))/((14)(q^(4))))# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1406 views around the world You can reuse this answer Creative Commons License