What is the distance between the following polar coordinates?: (2,(19pi)/12), (3,(7pi)/8)

1 Answer
Nov 20, 2017

ans=sqrt((2*cos(19/12pi)-3*cos(7/8pi))^2+(2*sin(19/12pi)-3*sin(7/8pi))^2)

Explanation:

x=rcostheta
y=rsintheta
x1=2*cos(19/12pi)
y1=2*sin(19/12pi)
x2=3*cos(7/8pi)
y2=3*sin(7/8pi)
dist=sqrt((x1-x2)^2+(y1-y2)^2
=sqrt((2*cos(19/12pi)-3*cos(7/8pi))^2+(2*sin(19/12pi)-3*sin(7/8pi))^2)