Question

The gas inside of a container exerts `16 Pa` of pressure and is at a temperature of `430 ^o K`. If the temperature of the gas changes to `150 ^oC` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

`"16.26 Pa"`

Explanation:

Gay-Lussac's law: For a given mass and constant volume of an ideal gas, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

Mathematically,

`P ∝ T`

`P_1/P_2 = T_1/T_2`

`P_2 = P_1 × T_2/T_1`

`P_2 = "16 Pa" × "430 K"/"(150 + 273)K" = "16.26 Pa"`