Question

If the initial temperature of an ideal gas at 2.250 atm is 62.00 °C, what final temperature would cause the pressure to be reduced to 1.600 atm?

Answer 1

`"238.2 Kelvin"`

Explanation:

Gay-Lussac's law: For a given mass and constant volume of an ideal gas, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

Mathematically,

`P ∝ T`

`P_f/P_i = T_f/T_i`

`T_f = T_i × P_f/P_i`

`T_f = "(62.00 + 273.15) Kelvin" × (1.600 cancel"atm")/(2.250 cancel"atm") = "238.2 Kelvin"`