Question

How many moles of HCl are required to completely neutralize 0.30 moles of `Ca(OH)_2`?

Answer 1

Why `0.60*mol`....

Explanation:

And how do we know?

Well, we interrogate the stoichiometric equation...

`Ca(OH)_2(s) + 2HCl(aq) rarr CaCl_2(aq) + 2H_2O(l)`

Two equiv of `HCl` are required per equiv `"calcium hydroxide"`..

What number of `HCl` molecules are required for equivalence?