How do you solve #2^ { x ^ { 2} - 34x - 2} = 32^ { 5- 8x }#?
1 Answer
Nov 28, 2017
Explanation:
Rewrite in a common base.
#2^(x^2 - 34x - 2) = (2^5)^(5 - 8x)#
#2^(x^2 - 34x - 2) = 2^(25 - 40x)#
We can now eliminate exponents.
#x^2 - 34x - 2 = 25 - 40x#
#x^2 + 6x - 27 = 0#
#(x + 9)(x - 3) = 0#
#x = -9 or 3#
Hopefully this helps!