How do you graph y=3/(2x) using asymptotes, intercepts, end behavior?

1 Answer
Nov 29, 2017

here is the graph:
enter image source here

Explanation:

To graph y=3/(2x:

Vertical asymptotes occur at the zeroes of the denominator.

D=2x
VA=0 and there are no holes.

There is a horizontal asymptote because the degree of the numerator is less than the degree of the denominator:

HA: deg N > deg D = 0

There is no slant asymptote.

Find Behaviour near V.A (generally +/-0.1 away)
the value is not important, you only need to know the sign of the result:

at x=0.1 = + (positive)
at x=-0.1 = - (negative)

so 0.1 will start in quadrant I in the top left corner at x=0.1 and -0.1 will start in quadrant III in the bottom corner at x=-0.1

There are no x intercepts.
There is no y intercept.

Draw your graph with smooth curves.