Question

How do you graph `2x+3y=12` using intercepts?

Answer 1

`"see explanation"`

Explanation:

`"to find the intercepts that is where the graph crosses"`
`"the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`x=0to0+3y=12rArry=4larrcolor(red)"y-intercept"`

`y=0to2x+0=12rArrx=6larrcolor(red)"x-intercept"`
graph{-2/3x+4 [-10, 10, -5, 5]}