Domain of #f(x)=ln(1+1/x)/x# ?

1 Answer
Dec 3, 2017

#D_f=(-oo,-1)∪(0,oo)#

Explanation:

The domain of a function is the maximal interval over which it's defined.

The #ln# function is defined over #RR# for positive real values.

Consider that if #|x|> 1# then #1"/"|x| < 1#. So we can say that #ln(1+1"/"x)# will be defined for all #x<-1# and obviously will be defined for all #x>0#.

We also see that #x!=0# since we have #x# in the denominator.

So #D_f=(-oo,-1)∪(0,oo)#