Question

What is the density in g/cm^3 of an iron ball that has a radius of 45.0 mm, and a mass of 300 g?

With steps please

Answer 1

The question states we have a "ball", or sphere, so we may calculate the volume,

`V = (4pir^3)/3`

`V = (4pi*((45.0mm)*(cm)/(10mm))^3)/3 approx 382cm^3`

From here, we may calculate density. Hence,

`(300g)/(382cm^3) approx (0.786g)/(cm^3)`

is the density of iron in this case, although this is a gross underestimation.