How do you solve #(6\times 4) + b = 60#?

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Answer 1 · 2017-12-05T01:57:52

See a solution process below:

First, execute the multiplication operation within the parenthesis:

#(color(red)(6) xx color(red)(4)) + b = 60#

#24 + b = 60#

Now, subtract #color(red)(24)# from each side of the equation to solve for #b# while keeping the equation balanced:

#24 - color(red)(24) + b = 60 - color(red)(24)#

#0 + b = 36#

#b = 36#