How do you solve #2x+2y-4z=8, 2x+y-z=6, -x-y+2z=2#?
1 Answer
Dec 15, 2017
This system of equations has no solution.
Explanation:
Given:
#{ (2x+2y-4z=8), (2x+y-z=6), (-x-y+2z=2) :}#
Note that adding twice the third equation to the first we get:
#0 = 12#
which is false.
So this system is inconsistent and has no solutions.
