A container with a volume of #18 L# contains a gas with a temperature of #150^o K#. If the temperature of the gas changes to #120 ^o K# without any change in pressure, what must the container's new volume be?
1 Answer
Dec 22, 2017
Explanation:
The ideal gas law gives:
#(P_1V_1)/T_1=(P_2V_2)/T_2#
Which for constant pressure becomes:
#V_1/T_1=V_2/T_2#
We can solve for
#V_2=(V_1T_2)/T_1#
We are given that:
#V_1=18"L"# #T_1=150"K"# #T_2=120"K"#
Substituting these values into the equation above,
#V_2=(18*120)/(150)#
#=14.4"L"#
Or,
