How do you use the chain rule to differentiate #cos(10csc10x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Timber Lin Dec 25, 2017 #100sin(10csc(10x))csc(10x)cot(10x)# Explanation: #d/dx(cos(10csc(10x)))=-sin(10csc(10x))*d/dx(10csc(10x))# (chain rule) #=-sin(10csc(10x))*10(-csc(10x)cot(10x))*d/dx(10x)# (chain rule again) #=10sin(10csc(10x))*(csc(10x)cot(10x))*10# #=100sin(10csc(10x))csc(10x)cot(10x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1307 views around the world You can reuse this answer Creative Commons License