How do you simplify #(10a^2+11a-6) ÷ (16-a^2)/(5a^2+18a-8)#?

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Answer 1 · 2017-12-26T15:51:53

#(-(5a-2)(10a^2+11a-6))/(a-4)#

First, rearrange the expression into

#(10a^2+11a-6)*(5a^2+18a-8)/(16-a^2)#

Then factor the second part of the expression

#(10a^2+11a-6)*[(5a-2)(a+4)]/[(4-a)(4+a)]#

Notice that #4+a# is the same thing as #a+4#, so you can cancel both terms to get:

#(10a^2+11a-6)*[(5a-2)]/[(4-a)]#

I like to put my letter variables in front, so I put a negative sign to balance it out, and my final equation becomes

#(-(5a-2)(10a^2+11a-6))/(a-4)#