Given a #180*mL# volume of gas at #0.740*"bar"#, how does its volume evolve at #1.025*"bar"#?

1 Answer
Dec 27, 2017

Well, we use old Boyle's law....#PV=k#...given that temperature AND amount of gas is CONSTANT....

Explanation:

And so we solve for #k# under different conditions...

#P_1V_1=P_2V_2#

#V_2=(P_1V_1)/P_2=(0.740*"bar"xx180*mL)/(1.025*"bar")=??*mL#...

Is the reduction in volume reasonable given the pressure change? Why or why not?