How do you normalize # (i -2j + 3k) #?

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Answer 1 · 2017-12-28T16:16:12

#1/sqrt14(hati-2hatj+3hatk)#

to normalize a vector means to change it to a unit vector, that is ensure that its magnitude is #=1#

#hatveca=(veca)/|veca|#

we ahve

#veca=hati-2hatj+3hatk#

#|a|14#

#=sqrt(1^2+2^2+3^2)=sqrt14#

#hatveca=1/sqrt14(hati-2hatj+3hatk)#