Question

Question #f4e73

Answer 1

Kinetic energy will become 8 times than first.

Explanation:

Kinetic energy(KE) `= 1/2 mv^2`
Let initial KE be `KE_i` and final KE be `KE_f`

`(KE_i)/(KE_f)=(1/2 m_iv_i^2)/(1/2 m_fv_f^2)`

`(KE_i)/(KE_f)=(2 m_iv_i^2)/(16 m_iv_i^2)`

`(KE_i)/(KE_f)=(1 )/(8)`

`KE_f=8KE_i`

So, kinetic energy will become 8 times than first.