The gas inside of a container exerts #9 Pa# of pressure and is at a temperature of #35 ^o K#. If the temperature of the gas changes to #20 ^oK#, what is the new pressure of the gas?

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Answer 1 · 2017-12-29T06:11:34

The new pressure is #=5.14Pa#

Apply Gay Lussac's Law

#P_1/T_1=P_2/T_2# at constant volume

The initial pressure is #P_1=9Pa#

The initial temperature is #T_1=35K#

The final temperature is #T_2=20K#

The final pressure is

#P_2=T_2/T_1*P_1=20/35*9=5.14Pa#