How do you differentiate #f(x)= (2 x^2 - x - 6 )/ (x- 1 )# using the quotient rule?
1 Answer
Dec 29, 2017
Explanation:
#"given "f(x)=(g(x))/(h(x))" then"#
#f'(x)=(h(x)g'(x)-g(x)h'(x))/(h(x))^2larrcolor(blue)"quotient rule"#
#g(x)=2x^2-x-6rArrg'(x)=4x-1#
#h(x)=x-1rArrh(x)=1#
#rArrf'(x)=((x-1)(4x-1)-(2x^2-x-6))/(x-1)^2#
#color(white)(rArrf'(x))=(2x^2-4x+7)/(x-1)^2#
