How do you use the chain rule to differentiate #y=7e^(2x)#?

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Answer 1 · 2018-01-02T02:11:45

#y'=14e^(2x)#

Pull the constant out:

#d/dx[7e^(2x)]->7d/dx[e^(2x)]#

Take the derivative of #e^(2x)#

#d/dx[e^(2x)]=e^(2x)*d/dx[2x]#

#=e^(2x)*2=2e^(2x)#

Therefore

#y'=7d/dx[e^(2x)]=7*2e^(2x)=14e^(2x)#