Find the equation of the pair of lines passing through the point #(2,3)# and perpendicular to the line pair #2x^2-xy-6y^2+4x+6y=0#?
1 Answer
Explanation:
Given:
Factor:
The equation of each line is:
To make lines that are perpendicular, we swap the coefficients and change the sign of one coefficient:
To find the values of
The equation of the lines are:
Write second line so that it is equal to 0:
Multiply the two lines:
graph{(2x^2-xy-6y^2+4x+6y)(6x^2-xy-2y^2-21x+14y)=0 [-10.25, 9.75, -3.64, 6.36]}