Question

A `3.6*L` volume of gas at `1.0*atm` is compressed to give a pressure of `2.5*atm`. What is the new volume?

Answer 1

Well, what does old Boyle's law say?

Explanation:

Boyle's law holds that at constant temperature, and constant mass of gas, the product `PV=k`....equivalently....`P_1V_1=P_2V_2`..

And so we solve for `V_2=(P_1V_1)/P_2`

`=(3.60*Lxx1.00*atm)/(2.50*atm)=??*L`