Question

How do you solve `2( 2w + 5) + 2w = 146`?

Answer 1

`w=68/3`

Explanation:

`"distribute the bracket on the left side of the equation"`

`4w+10+2w=146`

`rArr6w+10=146`

`"subtract 10 from both sides"`

`6wcancel(+10)cancel(-10)=146-10`

`rArr6w=136`

`"divide both sides by 6"`

`(cancel(6) w)/cancel(6)=136/6`

`rArrw=68/3" is the solution"`

Answer 2

`color(red)(w=22.67)`

Explanation:

1) Using BIDMAS or respectively BODMAS or similar, B stands for brackets, so first you multiply the bracket:

`color(red)(2*2w=4w)`
`color(red)(2*5=10)`

2) Re-input this into the equation, removing the brackets:

`therefore` `color(green)(4w+10+2w=146)`

3) Collecting like terms give us:

`color(blue)(6w+10=146)`

4) Solve like an equation:

`color(blue)(6w=136)(-10)`

`color(blue)(w=136/6=22.666...)`

`color(red)(w=22.67)`

Answer 3

`w=68/3`

Explanation:

Given:`color(white)("d")2(2w+5)+2w=146`

divide everything on both sides of the = by 2 giving:

`2w+5+w=73`

`3w+5=73`

Subtract 5 from both sides

`3w=68`

Divide both sides by 3

`w=68/3`