How do you find $f(g(4))$ given $f(x)=(x-2)^2; g(x)=x+3$ ?

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Answer 1 · 2018-01-09T16:11:31

$25$

$f(x)=(x-2)^2;color(red)(g(x)=x+3)$

$f(color(red)(g(4)))=f(color(red)(4+3))=f(7)$

$=(7-2)^2=5^2=25$

How do you find f(g(4))f(g(4)) given f(x)=(x-2)^2; g(x)=x+3f(x)=(x-2)^2; g(x)=x+3?