Question

How you solve this differential equation? `y'+5y=0`

Answer 1

`y=Ce^(−5x), C in RR`

Explanation:

`y'+5y=0`
`y'=-5y`
`(y')/y=-5`

`color(blue)((u')/u=ln'(u)`
`ln(y)'=-5`

`color(blue)"finding the primitive"`
`ln(y)=-5x+C`
`y=Ce^(-5x), C in RR`