Question

A balanced lever has two weights on it, the first with mass `1 kg` and the second with mass `3 kg`. If the first weight is `2 m` from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

O.67 meters

Explanation:

As the system is in equilibrium,so from the equation of rotational equilibrium we can say,net torque acting on the lever should be zero,
Hence we can write,
Torque created by the 1st mass=Torque created by the 2nd mass
Or, `1*g*2`=`3*g*x` (where x is that desired distance from the fulcrum)
Or,x = 0.67 meters