How do you graph #y=-1/2x +b#?

1 Answer
turksvids
Jan 13, 2018

see explanation.

Explanation:

For #y=-=1/2x+b# the #y#-intercept is #(0,b)#, which is a pretty generic point that depends on the value of #b#.

The slope of the line is #-1/2# so if #x# increases by 2, #y# must decrease by 1.

To graph this line, plot the point #(0,b)# and find a second point at #(2,b-1)#, draw your line through those points.

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