What is the Cartesian form of #(81,(24pi)/12)#?

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Answer 1 · 2018-01-16T18:26:46

#(81,0)#

polar form: #(r, theta)#
cartesian form: #(x,y)#

#x = r cos theta#
#y = r sin theta#

here, #r = 81, theta = (24pi)/12#
#theta = 2pi#

#r cos theta = 81 cos 2pi#

#= 81 * 1#

#= 81#

#r sin theta = 81 sin 2pi#

#= 81 * 0#

#= 0#

#x = 81, y = 0#

cartesian coordinates: #(81, 0)#