How do you find the domain and range of $root4(-4-7x)$ ?

Question

1759 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-17T13:33:22

The domain is $x in (-oo, -4/7]$ . The range is $y in [0,+oo)$

Let $y=(-4-7x)^(1/4)$

What's under the square root sign is $>=0$

Therefore,

$-4-7x>=0$

$7x<=-4$

$x<=-4/7$

The domain is $x in (-oo, -4/7]$

When $x=-4/7$ , $=>$ , $y=0$

When $x=-oo$ , $=>$ , $y=+oo$

The range is $y in [0,+oo)$

graph{(-4-7x)^(1/4) [-12.66, 12.65, -6.33, 6.33]}

How do you find the domain and range of root4(-4-7x)root4(-4-7x)?