Question

Question #0a47a

Answer 1

It can be done, but it’s a multi-stage calculation.

Explanation:

Firstly find the momentum from the wavelength (remembering to convert to m), next get a kinetic energy and finally convert to eV.

1) `p = h/lambda = (6.63xx10^-34)/(1xx10^-10) = 6.63xx10^-24` kgm/s

2) `E_k = p^2/(2m) = (6.63xx10^-24)^2/(2xx1.675xx10^-27) = 1.31xx10^-20` J

3) `eV = J /1.6xx10^-19 = (1.31xx10^-20)/(1.6xx10^-19) = 0.08` eV

Check the sums, but the logic is good!