The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #650 ^o K#. If the temperature of the gas changes to #220 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2018-01-20T18:50:14

The new pressure is #=11.4Pa#

Apply Gay Lussac 's Law

#"Pressure"/"Temperature"="Constant"# at #"Constant Volume"#

#P_1/T_1=P_2/T_2#

The initial pressure is #P_1=15Pa#

The initial temperature is #T_1=650K#

The final temperature is #T_2=220+273=493K#

The final pressure is

#P_2=T_2/T_1*T_2#

#=493/650*15#

#=11.4Pa#